Someone has already started making progress by creating this thread. Great! As requested, I'll outline a problem I'm currently grappling with:
I'm stuck on a particular exercise involving finding the focus and directrix of a parabola when given the equation. I've worked out that the vertex is at (2,-3) and the axis is parallel to the y-axis. From there, I can glean that the equation for the parabola is x = 4y + 5.
However, I'm unsure how to logically progress from here to find the requested focus and directrix. I'd appreciate some guidance on the thought process to employ in extracting the focus and directrix from this information.
That's a great question!
Since you've determined that the vertex is at (2, -3) and the parabola is aligned vertically with its axis parallel to the y-axis, you're on the right track.
The focus of a parabola is a very important point that helps us calculate the directrix. For a verticle parabola, the focus lies directly above or below the vertex, essentially 'on the same horizontal line' at a distance of the parabola's latus rectum. The latus rectum is the longest distance through the apex/vertex and is parallel to the axis.
So for this case, you'd calculate the focal point by moving a distance of 4 (which is half the latus rectum) horizontally from the vertex in either direction. This places the focus at (-1,-3) and (5,-3). The directrix then would be a horizontal line placed exactly between these two points.
You might also recall that the equation for the directrix of a parabola is typically shown as an equation of the form y = k, where 'k' is a constant. To find this, simply take the average of the y-coordinates of the vertex and the focus. In this case, it's (-3 + 3) / 2 = 0, thus the directrix is a horizontal line at y = 0.
Thus, the focus of the parabola is at (-1,-3) or (5,-3), and the directrix is the horizontal line y=0. hopefully, this helps!